Entering the central angle and one known property value (such as radius, chord length, arc length, area, etc.) to quickly compute the radius, chord length, arc length, area, and other properties of a circular segment.
A circular segment is the region enclosed by a circular arc and the chord corresponding to that arc. It is described by a central angle (in degrees or radians) and properties such as arc length, chord length, height, perimeter, and area.
Let θ be the central angle of the circular segment (in radians) and r be the radius of the circle.
The chord length is the straight-line distance between two points on the circle, calculated using the formula: \( \text{Chord Length} = 2 \times r \times \sin\left(\frac{\theta}{2}\right) \)
The arc length is the length of the circular arc, which can be calculated by: \( \text{Arc Length} = \theta \times r \)
The height is the perpendicular distance from the top of the circular segment to the chord, calculated as: \( h = r - \sqrt{r^2 - \left(\frac{\text{Chord Length}}{2}\right)^2} \) where Chord Length is the chord length.
The perimeter of the circular segment is the sum of the arc length and the chord length: \( P = \text{Arc Length} + \text{Chord Length} \)
The area of the circular segment is the area of the sector corresponding to the central angle minus the area of the triangle formed by the radius and chord: \( A = \frac{1}{2} r^2 (\theta - \sin\theta) \)
Solution:
Convert the angle to radians:
\( \theta = 60^\circ = \frac{60 \times \pi}{180} = \frac{\pi}{3} \text{ rad} \)
Chord Length:
\( \text{Chord Length} = 2 \times 10 \times \sin\left(\frac{\pi}{6}\right) = 20 \times \frac{1}{2} = 10 \)
Arc Length:
\( \text{Arc Length} = \theta \times r = \frac{\pi}{3} \times 10 \approx 10.47 \)
Height:
\( h = 10 - \sqrt{10^2 - \left(\frac{10}{2}\right)^2} = 10 - \sqrt{100 - 25} \approx 1.34 \)
Perimeter:
\( P = \text{Arc Length} + \text{Chord Length} = 10.47 + 10 = 20.47 \)
Area:
\( A = \frac{1}{2} \times 10^2 \times \left(\frac{\pi}{3} - \sin\left(\frac{\pi}{3}\right)\right) \approx 9.06 \)