Input the ratio and HCF of two numbers to quickly calculate their actual values.
Suppose the two numbers are \( x \) and \( y \), and their ratio is \( r_1 : r_2 \), with the highest common factor \( \text{HCF} \) given.
Assume the two numbers can be expressed as: \( x = k \cdot r_1, \quad y = k \cdot r_2 \) Here, \( k \) is a proportional coefficient. The ratio between the numbers is \( r_1 : r_2 \).
Since \( \text{HCF}(x, y) = k \cdot \text{HCF}(r_1, r_2) \), the proportional coefficient \( k \) can be calculated as: \( k = \frac{\text{HCF}}{\text{HCF}(r_1, r_2)} \)
Substitute \( k \) into the expressions for \( x \) and \( y \): \( x = k \times r_1 \) \( y = k \times r_2 \)
Solution:
1. Compute the HCF:
\( \text{HCF}(11, 15) = 1 \)
2. Compute the proportional coefficient \( k \):
\( k = \frac{13}{1} = 13 \)
3. Substitute \( k \) into the formulas for \( x \) and \( y \):
\( x = 13 \times 11 = 143 \)
\( y = 13 \times 15 = 195 \)
Result: The two numbers are 143 and 195.
Solution:
1. Compute the HCF:
\(\text{HCF}(3, 4) = 1 \)
2. Compute the proportional coefficient \( k \):
\( k = \frac{15}{1} = 15 \)
3. Substitute \( k \) into the formulas for \( x \) and \( y \):
\( x = 15 \times 3 = 45 \)
\( y = 15 \times 4 = 60 \)
Result: The two numbers are 45 and 60.