Input the sum and HCF of two numbers to calculate their actual values quickly.
Suppose the two numbers are \( x \) and \( y \), and their sum is \( S \), with the highest common factor \( \text{HCF} \) given.
Assume the two numbers can be expressed as: \( x = k \cdot a, \quad y = k \cdot b \) Here, \( k \) is the HCF, and \( a \) and \( b \) are two coprime integers (i.e., \( \text{HCF}(a, b) = 1 \)). The sum of the numbers is: \( x + y = k \cdot (a + b) = S \)
Using the sum \( S \) and the HCF, the proportional coefficient is given by: \( k = \text{HCF} \)
Since \( S = k \cdot (a + b) \), we can deduce: \( a + b = \frac{S}{\text{HCF}} \) List all pairs of integers that sum to \( a + b \) and check which ones are coprime.
Multiply \( k \) by \( a \) and \( b \) to find \( x \) and \( y \): \( x = k \times a \) \( y = k \times b \)
Solution:
1. Determine the proportional coefficient \( k \):
\( k = HCF = 27 \)
2. Calculate \( a + b \):
\( a + b = \frac{135}{27} = 5 \)
3. Find coprime pairs:
For \( a + b = 5 \), the coprime pairs are \( (1, 4) \) and \( (2, 3) \).
4. Calculate \( x \) and \( y \):
\( x_1 = 27 \times 1 = 27 \)
\( y_1 = 27 \times 4 = 108 \)
\( x_2 = 27 \times 2 = 54 \)
\( y_2 = 27 \times 3 = 81 \)
Result: The two numbers are \( (27, 108) \) or \( (54, 81) \).
Solution:
1. Determine the proportional coefficient \( k \):
\( k = HCF = 37 \)
2. Calculate \( a + b \):
\( a + b = \frac{629}{37} = 17 \)
3. Find coprime pairs:
For \( a + b = 17 \), the coprime pairs are:
\( (1, 16) \)
\( (2, 15) \)
\( (3, 14) \)
\( (4, 13) \)
\( (5, 12) \)
\( (6, 11) \)
\( (7, 10) \)
\( (8, 9) \)
4. Calculate \( x \) and \( y \):
\( x_1 = 37 \times 1 = 37 \)
\( y_1 = 37 \times 16 = 592 \)
\( x_2 = 37 \times 2 = 74 \)
\( y_2 = 37 \times 15 = 555 \)
…
\( x_8 = 37 \times 8 = 296 \)
\( y_8 = 37 \times 9 = 333 \)
Result: Possible pairs are (37, 592), (74, 555), (111, 518), (148, 481), (185, 444), (222, 407), (259, 370), (296, 333).